Friday, October 2, 2015

10055 : Hashmat the Brave Warrior


Problem:

Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to
fight against his opponents. Before Fighting he just calculates one thing, the difference between his soldier number and the opponent’s soldier number. From this difference he decides whether to fight or not. Hashmat’s soldier number is never greater than his opponent.

Input

The input contains two numbers in every line. These two numbers in each line denotes the number soldiers in Hashmat’s army and his opponent’s army or vice versa. The input numbers are not greater than 232. Input is terminated by ‘End of File’.

Output 

For each line of input, print the difference of number of soldiers between Hashmat’s army and his opponent’s army. Each output should be in seperate line.

Sample Input 
10 12 
10 14
100 200 

Sample Output
 2
 4
100

HINTS:
1. Use long int 
2. You can use labs in stdlib.h   . It takes long integer and return it's absolute value i.e mode of the number (  | x | is x is the number )

SOLUTION :


#include<iostream>
#include<stdlib.h>
using namespace std;
int main()
{
   long int a,b;
   while(cin>>a>>b)
   {
       cout<<labs(a-b)<<"\n";
   }

   return 0;
}


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